Gravitation Question 315

Question: Three particles P, Q and R are placed as per . Masses of P, Q and R are [3m,,,3m] and m respectively. The gravitational force on a fourth particle S of mass m is equal to

Options:

A) [3GM22d2] in ST direction only

B) [3GM22d2] in SQ direction and [3GM22d2] in SU direction

C) [3GM22d2] in SQ direction only

D)[3GM22d2] in SQ direction and [3GM22d2] in ST direction

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Answer:

Correct Answer: C

Solution:

  • In horizontal direction [Net,force=G3mm12d2cos30oGm24dcos60o]

    [=Gm28d2Gm28d2=0]

    In vertical direction, Net force [=G3m212d2cos60o+G3m23d2+Gm24dcos30o]

    [=3Gm224d2+3Gm23d2+3Gm28d]

    [=3Gm2d2[1+8+324]=3Gm22d2] along SQ-



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