Gravitation Question 30

Question: Weight of 1 kg becomes 1/6 on moon. If radius of moon is $ [1.768\times 10^{6},m] $ , then the mass of moon will be[RPET 1997]

Options:

A) $ [1.99\times 10^{30},kg] $

B) $ [7.56\times 10^{22},kg] $

C) $ [5.98\times 10^{24},kg] $

D) $ [7.65\times 10^{22},kg] $

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Answer:

Correct Answer: D

Solution:

$ [g_{m}=\frac{GM_{m}}{R_{m}^{2}}] $

and $ [g_{m}=\frac{g_{e}}{6}=\frac{9.8}{6}\ m/s^{2}] $ $ [=1.63\ m/s^{2}] $

Substituting $ [R_{m}=1.768\times 10^{6}m,] $ $ [g_{m}=1.63\ m/s^{2}] $

and $ [G=6.67\times {{10}^{-11}}N\text{-}m^{2}/kg^{2}] $

We get $ [M_{m}=7.65\times 10^{22}kg] $



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