SATHEE: Gravitation Question 30

Gravitation Question 30

Question: Weight of 1 kg becomes 1/6 on moon. If radius of moon is $[1.768 \times 10^{6}, m]$ , then the mass of moon will be[RPET 1997]

Options:

A) $[1.99 \times 10^{30}, k g]$

B) $[7.56 \times 10^{22}, k g]$

C) $[5.98 \times 10^{24}, k g]$

D) $[7.65 \times 10^{22}, k g]$

Show Answer

Answer:

Correct Answer: D

Solution:

$[g_{m} = \frac{G M_{m}}{R_{m}^{2}}]$

and $[g_{m} = \frac{g_{e}}{6} = \frac{9.8}{6} m / s^{2}]$ $[= 1.63 m / s^{2}]$

Substituting $[R_{m} = 1.768 \times 10^{6} m,]$ $[g_{m} = 1.63 m / s^{2}]$

and $[G = 6.67 \times 10^{- 11} N - m^{2} / k g^{2}]$

We get $[M_{m} = 7.65 \times 10^{22} k g]$

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Gravitation Question 30

Question: Weight of 1 kg becomes 1/6 on moon. If radius of moon is [1.768×106,m] , then the mass of moon will be[RPET 1997]

Options:

Answer:

Solution:

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Question: Weight of 1 kg becomes 1/6 on moon. If radius of moon is $[1.768 \times 10^{6}, m]$ , then the mass of moon will be[RPET 1997]