Gravitation Question 299

Question: Two particles of equal mass ’m’ go around a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle with respect to their centre of mass is

Options:

A) [Gm4R]

B) [Gm3R]

C) [Gm2R]

D) [GmR]

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Answer:

Correct Answer: A

Solution:

  • Here, centripetal force will be given by the gravitational force between the two particles.

    [Gm2(2R)2=mω2R]
    [Gm4R3=ω2ω=GM4R3]

    If the velocity of the two particles with respect to the centre of gravity is v then [v=Gm4R3×R=GM4R]



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