Gravitation Question 296
Question: A planet revolves about the sun in elliptical orbit. The areal velocity $ [\left( \frac{dA}{dt} \right)] $ of the planet is$ [4.0\times 10^{16} m/s] $ . The least distance between planet and the sun is$ [2\times 10^{12}m] $ . Then the maximum speed of the planet in km/s is
Options:
A) 10
B) 20
C) 30
D) 40
Show Answer
Answer:
Correct Answer: D
Solution:
- $ [\frac{L}{2m}=\frac{dA}{dt}] $ (L= angular momentum) $ [\frac{m{v_{\max }}{r_{\min }}}{2m}=\frac{dA}{dt};{v_{\max }}=\frac{2dA/dt}{{r_{\min }}}=40] $
