Gravitation Question 290

Question: Two identical solid copper spheres of radius R placed in contact with each other. The gravitational attracton between them is proportional to[Kerala PET 2005]

Options:

A)$ [R^{2}] $

B)$ [{{R}^{-2}}] $

C) $ [R^{4}] $

D)$ [{{R}^{-4}}] $

Show Answer

Answer:

Correct Answer: C

Solution:

$ [F=\frac{G\times m\times m}{{{(2R)}^{2}}}] $ =$ [\frac{G\times {{\left( \frac{4}{3}\pi R^{3}\rho\right)}^{2}}}{4R^{2}}] $ $ [=\frac{4}{9}{{\pi }^{2}}{{\rho }^{2}}R^{4}] $ \ $ [F\propto R^{4}] $



NCERT Chapter Video Solution

Dual Pane