SATHEE: Gravitation Question 290

Gravitation Question 290

Question: Two identical solid copper spheres of radius R placed in contact with each other. The gravitational attracton between them is proportional to[Kerala PET 2005]

Options:

A) $[R^{2}]$

B) $[R^{- 2}]$

C) $[R^{4}]$

D) $[R^{- 4}]$

Show Answer

Answer:

Correct Answer: C

Solution:

$[F = \frac{G \times m \times m}{{(2 R)}^{2}}]$ = $[\frac{G \times {(\frac{4}{3} π R^{3} ρ)}^{2}}{4 R^{2}}]$ $[= \frac{4}{9} π^{2} ρ^{2} R^{4}]$ \ $[F \propto R^{4}]$

Gravitation Question 290

Question: Two identical solid copper spheres of radius R placed in contact with each other. The gravitational attracton between them is proportional to[Kerala PET 2005]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Gravitation Question 290

Question: Two identical solid copper spheres of radius R placed in contact with each other. The gravitational attracton between them is proportional to[Kerala PET 2005]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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