Gravitation Question 281

Question: The gravitational force between two stones of mass 1 kg each separated by a distance of 1 metre in vacuum is [DPMT 1984]

Options:

A) Zero

B)$ [6.675\times {{10}^{-5}},newton] $

C) $ [6.675\times {{10}^{-11}},newton] $

D)$ [6.675\times {{10}^{-8}},newton] $

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Answer:

Correct Answer: C

Solution:

$ [F=G\frac{m_{1}m_{2}}{r^{2}}] $ $ [=6.675\times \frac{1\times 1}{1^{2}}\times {{10}^{-11}}=6.675\times {{10}^{-11}}N] $



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