SATHEE: Gravitation Question 277

Gravitation Question 277

Question: A satellite moves in a circle around the earth. The radius of this circle is equal to one half of the radius of the moon’s orbit. The satellite completes one revolution in [J&K CET 2005]

Options:

A) $[\frac{1}{2}]$ lunar month

B) $[\frac{2}{3}]$ lunar month

C) $[2^{- 3 / 2}]$ lunar month

D) $[2^{3 / 2}]$ lunar month

Show Answer

Answer:

Correct Answer: C

Solution:

Time period of revolution of moon around the earth= 1 lunar month. $[\frac{T_{s}}{T_{m}} = {(\frac{r_{s}}{r_{m}})}^{3 / 2} = {(\frac{1}{2})}^{3 / 2}]$ Þ $[T_{s} = 2^{- 3 / 2}]$ lunar month.

Gravitation Question 277

Question: A satellite moves in a circle around the earth. The radius of this circle is equal to one half of the radius of the moon’s orbit. The satellite completes one revolution in [J&K CET 2005]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Gravitation Question 277

Question: A satellite moves in a circle around the earth. The radius of this circle is equal to one half of the radius of the moon’s orbit. The satellite completes one revolution in [J&K CET 2005]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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