Gravitation Question 267

Question: Potential energy of a satellite having mass ?m? and rotating at a height of $ [6.4\times 10^{6}m] $ from the earth surface is [AIIMS 2000; CBSE PMT 2001; BHU 2001]

Options:

A) $ [-0.5,mgR_{e}] $

B) $ [-mgR_{e}] $

C) $ [-2,mgR_{e}] $

D) $ [4,mgR_{e}] $

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Answer:

Correct Answer: A

Solution:

Potential energy = $ [\frac{-GMm}{r}=\frac{GMm}{R_{e}+h}=\frac{-GMm}{2R_{e}}] $ = $ [-\frac{gR_{e}^{2}m}{2R_{e}}] $ $ [=-\frac{1}{2}mgR_{e}] $ $ [=-0.5mgR_{e}] $



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