Gravitation Question 259

Question: A geo-stationary satellite is orbiting the earth at a height of 6 R above the surface of earth, R being the radius of earth. The time period of another satellite at a height of 2.5 R from the surface of earth is [UPSEAT 2002; AMU (Med.) 2002; Pb. PET 2003]

Options:

A) 10 hr

B) $ [(6/\sqrt{2}),hr] $

C) 6 hr

D) $ [6\sqrt{2},hr] $

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Answer:

Correct Answer: D

Solution:

Distances of the satellite from the centre are 7R and 3.5R respectively.

$ [\frac{T_{2}}{T_{1}}={{\left( \frac{R_{2}}{R_{1}} \right)}^{3/2}},$

$\Rightarrow T_{2}=24,{{\left( \frac{3.5R}{7R} \right)}^{3/2}}=6\sqrt{2},hr] $



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