Gravitation Question 220

Question: The ratio of diameters of two wires of same material is n: 1. The length of each wire is 4 m. On applying the same load, the increases in the length of the thin wire will be (n>) $

Options:

A) $ [n^{2}times] $

B) $ [{{n}^{{}}}times] $

C) $ [2{{n}^{{}}}times] $

D) $ [{{(2n+1)}^{{}}}times] $

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Answer:

Correct Answer: A

Solution:

  • $ [Y=\frac{F/a}{\Delta l/l}=\frac{Fl}{a\Delta l}] $ Or $ [Y=\frac{Fl\times 4}{\pi D^{2}\times \Delta l}] $ or $ [\Delta l\propto \frac{1}{D^{2}}] $ or $ [\frac{\Delta l_{2}}{\Delta l_{1}}=\frac{D_{1}^{2}}{D_{2}^{2}}=\frac{n^{1}}{1}] $


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