Gravitation Question 2
Question: The time period of a simple pendulum on a freely moving artificial satellite is [CPMT 1984; AFMC 2002]
Options:
A) Zero
B) 2 sec
C) 3 sec
D) Infinite
Show Answer
Answer:
Correct Answer: D
Solution:
Time period of simple pendulum $ [T=2\pi \sqrt{\frac{l}{g’}}] $ In artificial satellite $ [g’=0] $ \ T = infinite.
