SATHEE: Gravitation Question 197

Gravitation Question 197

Question: The maximum and minimum distances of a comet from the sun are $[8 \times 10^{12}, m]$ and $[1.6 \times 10^{12}, m]$ . If its velocity when nearest to the sun is 60 m/s, what will be its velocity in m/s when it is farthest [Orissa 2001]

Options:

A) 12

B) 60

C) 112

D) 6

Show Answer

Answer:

Correct Answer: A

Solution:

By conservation of angular momentum mvr= constant $[v_{min} \times r_{max} = v_{max} \times r_{min}]$ $[v_{min} = \frac{60 \times 1.6 \times 10^{12}}{8 \times 10^{12}} = \frac{60}{5} = 12, m / s]$

Gravitation Question 197

Question: The maximum and minimum distances of a comet from the sun are $[8 \times 10^{12}, m]$ and $[1.6 \times 10^{12}, m]$ . If its velocity when nearest to the sun is 60 m/s, what will be its velocity in m/s when it is farthest [Orissa 2001]

Options:

Answer:

Solution:

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Gravitation Question 197

Question: The maximum and minimum distances of a comet from the sun are [8×1012,m] and [1.6×1012,m] . If its velocity when nearest to the sun is 60 m/s, what will be its velocity in m/s when it is farthest [Orissa 2001]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: The maximum and minimum distances of a comet from the sun are $[8 \times 10^{12}, m]$ and $[1.6 \times 10^{12}, m]$ . If its velocity when nearest to the sun is 60 m/s, what will be its velocity in m/s when it is farthest [Orissa 2001]