Gravitation Question 193

Question: The period of revolution of planet A around the sun is 8 times that of B. The distance of A from the sun is how many times greater than that of B from the sun [CBSE PMT 1997; BHU 2001]

Options:

A) 2

B) 3

C) 4

D) 5

Show Answer

Answer:

Correct Answer: C

Solution:

$ [\frac{T_{A}}{T_{B}}={{\left( \frac{r_{A}}{r_{B}} \right)}^{3/2}}] $ $ [\Rightarrow 8={{\left( \frac{r_{A}}{r_{B}} \right)}^{3/2}}] $ $ [\Rightarrow r_{A}={{(8)}^{2/3}}r_{B}] $ $ [=4r_{B}.] $



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