SATHEE: Gravitation Question 193

Gravitation Question 193

Question: The period of revolution of planet A around the sun is 8 times that of B. The distance of A from the sun is how many times greater than that of B from the sun [CBSE PMT 1997; BHU 2001]

Options:

A) 2

B) 3

C) 4

D) 5

Show Answer

Answer:

Correct Answer: C

Solution:

$[\frac{T_{A}}{T_{B}} = {(\frac{r_{A}}{r_{B}})}^{3 / 2}]$ $[\Rightarrow 8 = {(\frac{r_{A}}{r_{B}})}^{3 / 2}]$ $[\Rightarrow r_{A} = {(8)}^{2 / 3} r_{B}]$ $[= 4 r_{B} .]$

Gravitation Question 193

Question: The period of revolution of planet A around the sun is 8 times that of B. The distance of A from the sun is how many times greater than that of B from the sun [CBSE PMT 1997; BHU 2001]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Gravitation Question 193

Question: The period of revolution of planet A around the sun is 8 times that of B. The distance of A from the sun is how many times greater than that of B from the sun [CBSE PMT 1997; BHU 2001]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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