Gravitation Question 193
Question: The period of revolution of planet A around the sun is 8 times that of B. The distance of A from the sun is how many times greater than that of B from the sun [CBSE PMT 1997; BHU 2001]
Options:
A) 2
B) 3
C) 4
D) 5
Show Answer
Answer:
Correct Answer: C
Solution:
$ [\frac{T_{A}}{T_{B}}={{\left( \frac{r_{A}}{r_{B}} \right)}^{3/2}}] $ $ [\Rightarrow 8={{\left( \frac{r_{A}}{r_{B}} \right)}^{3/2}}] $ $ [\Rightarrow r_{A}={{(8)}^{2/3}}r_{B}] $ $ [=4r_{B}.] $
