SATHEE: Gravitation Question 188

Gravitation Question 188

Question: The rotation period of an earth satellite close to the surface of the earth is 83 minutes. The time period of another earth satellite in an orbit at a distance of three earth radii from its surface will be[MP PMT 1994]

Options:

A) 83 minutes

B) $[83 \times \sqrt{8}]$ minutes

C) 664 minutes

D) 249 minutes

Show Answer

Answer:

Correct Answer: C

Solution:

For first satellite $[r_{1} = R]$ and $[T_{1} = 83 m i n u t e]$ For second satellite $[r_{2} = 4 R]$ $[T_{2} = T_{1} {(\frac{r_{2}}{r_{1}})}^{3 / 2} = T_{1} {(4)}^{3 / 2} = 8 T_{1} = 8 \times 83]$ =664 minutes

Gravitation Question 188

Question: The rotation period of an earth satellite close to the surface of the earth is 83 minutes. The time period of another earth satellite in an orbit at a distance of three earth radii from its surface will be[MP PMT 1994]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Gravitation Question 188

Question: The rotation period of an earth satellite close to the surface of the earth is 83 minutes. The time period of another earth satellite in an orbit at a distance of three earth radii from its surface will be[MP PMT 1994]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu