Gravitation Question 180
Question: The period of a satellite in a circular orbit of radius R is T, the period of another satellite in a circular orbit of radius 4R is [CPMT 1982; MP PET/PMT 1998; AIIMS 2000; CBSE PMT 2002]
Options:
A) 4T
B) T/4
C) 8T
D)T/8
Show Answer
Answer:
Correct Answer: C
Solution:
$ [\frac{T_{1}}{T_{2}}={{\left( \frac{R_{1}}{R_{2}} \right)}^{3/2}}={{\left( \frac{R}{4R} \right)}^{3/2}}\Rightarrow ,T_{2}=8T_{1}] $
