Gravitation Question 180

Question: The period of a satellite in a circular orbit of radius R is T, the period of another satellite in a circular orbit of radius 4R is [CPMT 1982; MP PET/PMT 1998; AIIMS 2000; CBSE PMT 2002]

Options:

A) 4T

B) T/4

C) 8T

D)T/8

Show Answer

Answer:

Correct Answer: C

Solution:

$ [\frac{T_{1}}{T_{2}}={{\left( \frac{R_{1}}{R_{2}} \right)}^{3/2}}={{\left( \frac{R}{4R} \right)}^{3/2}}\Rightarrow ,T_{2}=8T_{1}] $



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