Gravitation Question 168

Question:The acceleration due to gravity on a planet is same as that on earth and its radius is four times that of earth. What will be the value of escape velocity on that planet if it is $ [v_{e}] $ on earth[RPET 2002]

Options:

A) $ [v_{e}] $

B) $ [2v_{e}] $

C) $ [4v_{e}] $

D) $ [\frac{v_{e}}{2}] $

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Answer:

Correct Answer: B

Solution:

$ [v=\sqrt{2gR}] $

Þ $ [\frac{v_{p}}{v_{e}}=\sqrt{\frac{g_{p}}{g_{e}}\times \frac{R_{p}}{R_{e}}}=\sqrt{1\times 4}=2] $ \ $ [v_{p}=2v_{e}] $



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