SATHEE: Gravitation Question 140

Gravitation Question 140

Question: The escape velocity for a rocket from earth is 11.2 km/sec. Its value on a planet where acceleration due to gravity is double that on the earth and diameter of the planet is twice that of earth will be in km/sec[NCERT 1983; CPMT 1990; MP PMT 2000; UPSEAT 1999]

Options:

A) 11.2

B) 5.6

C) 22.4

D) 53.6

Show Answer

Answer:

Correct Answer: C

Solution:

$[\frac{v_{p}}{v_{e}} = \sqrt{\frac{g_{p}}{g_{e}} \times \frac{R_{p}}{R_{e}}}]$ = $[\sqrt{2 \times 2} = 2]$ Þ $[v_{p} = 2 \times v_{e} = 2 \times 11.2 = 22.4 k m / s]$

Gravitation Question 140

Question: The escape velocity for a rocket from earth is 11.2 km/sec. Its value on a planet where acceleration due to gravity is double that on the earth and diameter of the planet is twice that of earth will be in km/sec[NCERT 1983; CPMT 1990; MP PMT 2000; UPSEAT 1999]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Gravitation Question 140

Question: The escape velocity for a rocket from earth is 11.2 km/sec. Its value on a planet where acceleration due to gravity is double that on the earth and diameter of the planet is twice that of earth will be in km/sec[NCERT 1983; CPMT 1990; MP PMT 2000; UPSEAT 1999]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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