SATHEE: Gravitation Question 132

Gravitation Question 132

Question: A body is projected vertically upwards from the surface of a planet of radius R with a velocity equal to half the escape velocity for that planet. The maximum height attained by the body is [KCET (Engg./Med.) 2002]

Options:

A) R/3

B) R/2

C) R/4

D) R/5

Show Answer

Answer:

Correct Answer: A

Solution:

If body is projected with velocity v $[(v < v_{e})]$ then height up to which it will rise, $[h = \frac{R}{\frac{v_{e}^{2}}{v^{2}} - 1}]$ $[v = \frac{v_{e}}{2}]$ (given) \ $[h = \frac{R}{{(\frac{v_{e}}{v_{e} / 2})}^{2} - 1} = \frac{R}{4 - 1} = \frac{R}{3}]$

Gravitation Question 132

Question: A body is projected vertically upwards from the surface of a planet of radius R with a velocity equal to half the escape velocity for that planet. The maximum height attained by the body is [KCET (Engg./Med.) 2002]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Gravitation Question 132

Question: A body is projected vertically upwards from the surface of a planet of radius R with a velocity equal to half the escape velocity for that planet. The maximum height attained by the body is [KCET (Engg./Med.) 2002]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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