SATHEE: Gravitation Question 131

Gravitation Question 131

Question: A body of mass m kg. starts falling from a point2R above the Earth’s surface. Its kinetic energy when it has fallen to a point ?R? above the Earth’s surface [R-Radius of Earth, M-Mass of Earth, G-Gravitational Constant] [MP PMT 2002]

Options:

A) $[\frac{1}{2} \frac{G M m}{R}]$

B) $[\frac{1}{6} \frac{G M m}{R}]$

C) $[\frac{2}{3} \frac{G M m}{R}]$

D) $[\frac{1}{3} \frac{G M m}{R}]$

Show Answer

Answer:

Correct Answer: B

Solution:

Potential energy $[U = \frac{- G M m}{r} = - \frac{G M m}{R + h}]$ $[U_{i n i t i a l} = - \frac{G M m}{3 R}]$ and $[U_{f i n a l} = - \frac{- G M m}{2 R}]$ Loss in PE = gain in $[K E = \frac{G M m}{2 R} - \frac{G M m}{3 R} = \frac{G M m}{6 R}]$

Gravitation Question 131

Question: A body of mass m kg. starts falling from a point2R above the Earth’s surface. Its kinetic energy when it has fallen to a point ?R? above the Earth’s surface [R-Radius of Earth, M-Mass of Earth, G-Gravitational Constant] [MP PMT 2002]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Gravitation Question 131

Question: A body of mass m kg. starts falling from a point2R above the Earth’s surface. Its kinetic energy when it has fallen to a point ?R? above the Earth’s surface [R-Radius of Earth, M-Mass of Earth, G-Gravitational Constant] [MP PMT 2002]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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