SATHEE: Gravitation Question 111

Gravitation Question 111

Question: In order to make the effective acceleration due to gravity equal to zero at the equator, the angular velocity of rotation of the earth about its axis should be $[(g = 10, m s^{- 2}]$ and radius of earth is 6400 kms) [Roorkee 2000]

Options:

A) $[0, r a d, \sec^{- 1}]$

B) $[\frac{1}{800} r a d, s e c^{- 1}]$

C) $[\frac{1}{80} r a d, s e c^{- 1}]$

D) $[\frac{1}{8} r a d, s e c^{- 1}]$

Show Answer

Answer:

Correct Answer: B

Solution:

$[g^{'} = g - ω^{2} R \cos^{2} λ,]$ For weightlessness at equator $[λ = 0]$ and $[g^{'} = 0]$ \ $[0 = g - ω^{2} R]$ Þ $[ω = \sqrt{\frac{g}{R}} = \frac{1}{800} \frac{r a d}{s}]$

Gravitation Question 111

Question: In order to make the effective acceleration due to gravity equal to zero at the equator, the angular velocity of rotation of the earth about its axis should be $[(g = 10, m s^{- 2}]$ and radius of earth is 6400 kms) [Roorkee 2000]

Options:

Answer:

Solution:

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Gravitation Question 111

Question: In order to make the effective acceleration due to gravity equal to zero at the equator, the angular velocity of rotation of the earth about its axis should be [(g=10,ms−2] and radius of earth is 6400 kms) [Roorkee 2000]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: In order to make the effective acceleration due to gravity equal to zero at the equator, the angular velocity of rotation of the earth about its axis should be $[(g = 10, m s^{- 2}]$ and radius of earth is 6400 kms) [Roorkee 2000]