SATHEE: Gravitation Question 105

Gravitation Question 105

Question: Imagine a light planet revolving around a very massive star in a circular orbit of radius R with a period of revolution T. If the gravitational force of attraction between planet and star is proportional to $[R^{- \frac{5}{2}}]$ , then $[T^{2}]$ is proportional to[IIT 1989; RPMT 1997]

Options:

A) $[R^{3}]$

B) $[R^{7 / 2}]$

C) $[R^{5 / 2}]$

D) $[R^{3 / 2}]$

Show Answer

Answer:

Correct Answer: B

Solution:

For revolution of planet centripetal force is provided by gravitational force of attraction $[m ω^{2} R \propto R^{- 5 / 2}]$ Þ $[\frac{1}{T^{2}} \propto R^{- 7 / 2}]$ $[\Rightarrow T^{2} \propto R^{7 / 2}]$

Gravitation Question 105

Question: Imagine a light planet revolving around a very massive star in a circular orbit of radius R with a period of revolution T. If the gravitational force of attraction between planet and star is proportional to $[R^{- \frac{5}{2}}]$ , then $[T^{2}]$ is proportional to[IIT 1989; RPMT 1997]

Options:

Answer:

Solution:

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Gravitation Question 105

Question: Imagine a light planet revolving around a very massive star in a circular orbit of radius R with a period of revolution T. If the gravitational force of attraction between planet and star is proportional to [R−52] , then [T2] is proportional to[IIT 1989; RPMT 1997]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Imagine a light planet revolving around a very massive star in a circular orbit of radius R with a period of revolution T. If the gravitational force of attraction between planet and star is proportional to $[R^{- \frac{5}{2}}]$ , then $[T^{2}]$ is proportional to[IIT 1989; RPMT 1997]