Electrostatics Question 92

Question: A parallel plate air capacitor is charged to a potential difference of V. After disconnecting the battery, distance between the plates of the capacitor is increased using an insulating handle. As a result, the potential difference between the plates [KCET 1999]

Options:

A) Decreases

B) Increases

C) Becomes zero

D) Does not change

Show Answer

Answer:

Correct Answer: B

Solution:

$ V=\frac{Q}{C} $ =$ \frac{Qd}{{\varepsilon _{0}}KA} $

therefore $ V\propto d $



NCERT Chapter Video Solution

Dual Pane