Electrostatics Question 814

Question: A capacitor of capacity $ C _{1} $ is charged up to V volt and then connected to an uncharged capacitor of capacity $ C _{2}. $ Then final potential difference across each will be

Options:

A) $ \frac{C _{2}V}{C _{1}+C _{2}} $

B) $ ( 1+\frac{C _{2}}{C _{1}} )V $

C) $ \frac{C _{1}V}{C _{1}+C _{2}} $

D) $ ( 1-\frac{C _{2}}{C _{1}} )V $

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Answer:

Correct Answer: C

Solution:

[c] Common potential $ V=\frac{C _{1}V+C _{2}\times 0}{C _{1}+C _{2}} $

$ =\frac{C _{1}}{C _{1}+C _{2}}V $



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