SATHEE: Electrostatics Question 814

Electrostatics Question 814

Question: A capacitor of capacity $C_{1}$ is charged up to V volt and then connected to an uncharged capacitor of capacity $C_{2} .$ Then final potential difference across each will be

Options:

A) $\frac{C_{2} V}{C_{1} + C_{2}}$

B) $(1 + \frac{C_{2}}{C_{1}}) V$

C) $\frac{C_{1} V}{C_{1} + C_{2}}$

D) $(1 - \frac{C_{2}}{C_{1}}) V$

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Common potential $V = \frac{C_{1} V + C_{2} \times 0}{C_{1} + C_{2}}$

$= \frac{C_{1}}{C_{1} + C_{2}} V$

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Electrostatics Question 814

Question: A capacitor of capacity C1 is charged up to V volt and then connected to an uncharged capacitor of capacity C2. Then final potential difference across each will be

Options:

Answer:

Solution:

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Question: A capacitor of capacity $C_{1}$ is charged up to V volt and then connected to an uncharged capacitor of capacity $C_{2} .$ Then final potential difference across each will be