Electrostatics Question 796

Question: Two identical thin rings each of radius R meters are coaxially placed at a distance R meters apart. If Q1 coulomb and Q2 coulomb are respectively the charges uniformly spread on the two rings, the work done in moving a charge q from the center of one ring to that of other is

Options:

A) zero

B) q(Q1Q2)(21)2.4πε0R

C) q2(Q1+Q2)4πε0R

D) q(Q1+Q2)(2+1)2.4πε0R

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Work done W21=(V1V2)q

V=14π0[Q1R+Q22R] and V2=14π0[Q2R+Q12R]

Thus,W21=q(Q1Q2)(21)2.4π0R.



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