Electrostatics Question 785

Question: A charge +q fixed at each of the points x=x0,x=3x0,x=5x0…. up to ∞ on X-axis and charge -q is fixed on each of the points x=2x0,x=4x0,…. up to ∞ . Here x0 is a positive constant. Take the potential at a point due to a charge Q at a distance r form it to be Q4πε0r, then the potential at the origin due to above system of charges will be:

Options:

A) zero

B) infinite

C) q8πε0x0loge2

D) qloge24πε0x0

Show Answer

Answer:

Correct Answer: D

Solution:

[d] V=14πε0[qx0+q3x0+q5x0+…]

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