Electrostatics Question 781

Question: A charge of 3 coulomb moving in uniform electric field experiences a force of 3000 newton. The potential difference between the two points situated in a field at a distance of 1 cm from each other will be:

Options:

A) 100

B) 5000

C) 10

D) 50

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Force on a charge m an electric field is

$ F=qE $

But $ E=\frac{V}{d}\text{ }\therefore F=\frac{qV}{d} $

$ \text{or }V=\frac{Fd}{q}=\frac{300N\times 1\times {{10}^{-2}}m}{3C}=10volt $



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