Electrostatics Question 781
Question: A charge of 3 coulomb moving in uniform electric field experiences a force of 3000 newton. The potential difference between the two points situated in a field at a distance of 1 cm from each other will be:
Options:
A) 100
B) 5000
C) 10
D) 50
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Force on a charge m an electric field is
$ F=qE $
But $ E=\frac{V}{d}\text{ }\therefore F=\frac{qV}{d} $
$ \text{or }V=\frac{Fd}{q}=\frac{300N\times 1\times {{10}^{-2}}m}{3C}=10volt $
