Electrostatics Question 771

Question: A plastic disc is charged on one side with a uniform surface charge density σ and then three quadrant of the disk are removed. The remaining quadrant , with V=0 at infinity, the potential due to the remaining quadrant point P is

Options:

A) σ20[(r2+R2)1/2r]

B) σ20[Rr]

C) σ80[(r2+R2)1/2r]

D) none of these

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Answer:

Correct Answer: C

Solution:

[c] The potential at P due to whole disc is

V=σ20[R2+r2r].

Now potential due to quarter disc,

V=V4=σ80[R2+r2r].



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