Electrostatics Question 769
Question: Two metal pieces having a potential difference of 800 V are 0.02 m apart horizontally. A particle of mass $ 1.96\times {{10}^{-15}}kg $ is suspended in equilibrium between the plates. If e is the elementary charge, then charge on the particle is
Options:
A) 8
B) 6
C) 0.1
D) 3
Show Answer
Answer:
Correct Answer: D
Solution:
[d] In equilibrium, $ F=qE=( ne )\frac{V}{d}=mg $
$ n=\frac{mgd}{eV}=\frac{1.96\times {{10}^{-15}}\times 9.8\times 0.02}{1.6\times {{10}^{-19}}\times 800}=3 $
