Electrostatics Question 765

Question: If the electrostatic potential were given by ϕ=ϕ0(x2+y2+z2), where is constant, then the charge density giving rise to the above potential would be.

Options:

A) 0

B) 6ϕ0ε0

C) 2ϕ0ε0

D) 6ϕ0ε0

Show Answer

Answer:

Correct Answer: B

Solution:

[b] E=ϕ=ϕ02[xi^+yi^+zx^]

=ε0.E=2ε0ϕ0.(xi^+yi^+zx^)

n=6ϕ0ε0



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