SATHEE: Electrostatics Question 764

Electrostatics Question 764

Question: Two equally charged spheres of radii a and b are connected together. What will be the ratio of electric field intensity on their surfaces?

Options:

A) $\frac{a}{b}$

B) $\frac{a^{2}}{b^{2}}$

C) $\frac{b}{a}$

D) $\frac{b^{2}}{a^{2}}$

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Let charge on each sphere =q When they are connected together their Now let charge on

$a = q,$ and on $b = 2 q - q_{1}$

$\Rightarrow V_{a} = V_{b} or \frac{1}{4 π ε_{0}} \frac{q_{1}}{a} = \frac{1}{4 π ε_{0}} \frac{2 q - q_{1}}{b}$

$\Rightarrow \frac{q_{1}}{2 q - q_{1}} = \frac{a}{b}$

$\frac{E_{a}}{E_{b}} = \frac{\frac{1.}{4 π ε_{0}} \frac{q_{1}}{a^{2}}}{\frac{1}{4 π ε_{0}} \frac{q_{2}}{b^{2}}} = (\frac{q_{1}}{2 q - q_{1}}) \frac{b^{2}}{a^{2}}$

$= \frac{a}{b} . \frac{b^{2}}{a^{2}} = \frac{b}{a} = b : a$

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Electrostatics Question 764

Question: Two equally charged spheres of radii a and b are connected together. What will be the ratio of electric field intensity on their surfaces?

Options:

Answer:

Solution:

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