Electrostatics Question 76

Question: The plates of a parallel plate capacitor of capacity 50μC are charged to a potential of 100 volts and then separated from each other so that the distance between them is doubled. How much is the energy spent in doing so [MP PET 1997; JIPMER 2000]

Options:

A) 25×10−2J

B) −12.5×10−2J

C) −25×10−2J

D) 12.5×10−2J

Show Answer

Answer:

Correct Answer: A

Solution:

Wext=12C′V′2−12CV2

=(12)(C2)(2V)2−12CV2=12CV2

Wext=12×50×10−6×(100)2=25×10−2J

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