SATHEE: Electrostatics Question 750

Electrostatics Question 750

Question: Four identical particles each of mass m and charge q are kept at the four comers of a square of length L. The final velocity of these particles after setting them free will be

Options:

A) ${[\frac{K q^{2}}{m L} (5.4)]}^{1 / 2}$

B) ${[\frac{K q^{2}}{m L} (1.35)]}^{1 / 2}$

C) ${[\frac{K q^{2}}{m L} (2.7)]}^{1 / 2}$

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Potential energy of the system

$4 \times \frac{K}{2} (\frac{q^{2}}{L} + \frac{q^{2}}{L} + \frac{q^{2}}{L \sqrt{2}}) = 5.4 \frac{K q^{2}}{L}$

= Final kinetic energy of the system = $4 \times \frac{1}{2} m v^{2} = 2 m v^{2}$

$∴ v = {[\frac{K q^{2}}{m L} (2.7)]}^{1 / 2}$

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Electrostatics Question 750

Question: Four identical particles each of mass m and charge q are kept at the four comers of a square of length L. The final velocity of these particles after setting them free will be

Options:

Answer:

Solution:

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