SATHEE: Electrostatics Question 738

Electrostatics Question 738

Question: shows a uniformly charged hemisphere of radius R. It has a volume charge density $ρ .$ If the electric field at a point 2R, above its center is E, then what is the electric field at the point 2R below its center?

Options:

A) $ρ R / 6 ε_{0} + E$

B) $ρ R / 12 ε_{0} - E$

C) $- ρ R / 6 ε_{0} + E$

D) $ρ R / 12 ε_{0} + E$

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Let us complete the sphere.

Electric field due to upper part at B = E (given) Electric field B = electric field due to fall sphere electric field due to upper part at B=electric field due to full sphere -electric field due to upper part

$= \frac{k Q}{{(2 R)}^{2}} - E$

$= \frac{1}{4 π ε_{0}} \frac{ρ (4 / 3) π R^{3}}{4 R^{2}} - E$

$= \frac{ρ R}{12 ε_{0}} - E$

Electrostatics Question 738

Question: shows a uniformly charged hemisphere of radius R. It has a volume charge density $ρ .$ If the electric field at a point 2R, above its center is E, then what is the electric field at the point 2R below its center?

Options:

Answer:

Solution:

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Electrostatics Question 738

Question: shows a uniformly charged hemisphere of radius R. It has a volume charge density ρ. If the electric field at a point 2R, above its center is E, then what is the electric field at the point 2R below its center?

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: shows a uniformly charged hemisphere of radius R. It has a volume charge density $ρ .$ If the electric field at a point 2R, above its center is E, then what is the electric field at the point 2R below its center?