SATHEE: Electrostatics Question 735

Electrostatics Question 735

Question: A disc of radius a/4 having a uniformly distributed charge 6C is placed in the x-y plane with its center at (-a/2, 0, 0). A rod of length a carrying a uniformly distributed charge 8C is placed on the x-axis from $x = a / 4$ to $x = 5 a / 4$ . Two point charges -7C and 3C are placed at (a/4, -a/4, 0) and (-3a/4, 3a/4, 0), respectively. Consider a cubical surface formed by six surfaces $x = \pm a / 2, y = \pm a / 2, z = \pm a / 2.$ The electric flux through this cubical surface is

Options:

A) $\frac{- 2 C}{ε_{0}}$

B) $\frac{2 C}{ε_{0}}$

C) $\frac{10 C}{ε_{0}}$

D) $\frac{12 C}{ε_{0}}$

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Answer:

Correct Answer: A

Solution:

[a] It is clear that the charge enclosed in the cubical surface is $3 C + 2 C - 7 C = - 2 C .$

therefore the electric flux through the cube is $ϕ = \frac{q_{i n}}{ε_{0}} = \frac{- 2 C}{ε_{0}}$

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Electrostatics Question 735

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