Electrostatics Question 734

Question: A solid sphere of radius R has a charge Q distributed in its volume with a charge densityρ=kra , where k and an are constants and r is the distance from its center. If the electric field at r=R2 is 18 times that at r=R , the value of a is.

Options:

A) 3

B) 5

C) 2

D) both [a] and [b]

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Using Gauss’s law, we have E.dA=10(ρdv)=100Rkra×4πr2dr

or E×4πr2=(4πk0)R(a+3)(a+3) 

E1=kR(a+1)0(a+3)

For r=R2E2

=k(R2)a+10(a+3)=18kR(a+1)0(a+3)

21a+1=18 or a=2.



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