SATHEE: Electrostatics Question 732

Electrostatics Question 732

Question: Consider an electric field $\vec{E} = E_{0} \hat{x}$ where $E_{0}$ is a constant. The flux through the shaded area () due to this field is

Options:

A) $2 E_{0} a^{2}$

B) $\sqrt{2} E_{0} a^{2}$

C) $E_{0} a^{2}$

D) $\frac{E_{0} a^{2}}{\sqrt{2}}$

Show Answer

Answer:

Correct Answer: C

Solution:

[c] $\int_{}^{} \vec{E} . \vec{d A} = ϕ$

$\Rightarrow ϕ = E_{0} (a \times a \sqrt{2}) \cos 45^{\circ} - E_{0} a^{2}$

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Electrostatics Question 732

Question: Consider an electric field E→=E0x^ where E0 is a constant. The flux through the shaded area () due to this field is

Options:

Answer:

Solution:

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Question: Consider an electric field $\vec{E} = E_{0} \hat{x}$ where $E_{0}$ is a constant. The flux through the shaded area () due to this field is