Electrostatics Question 732

Question: Consider an electric field $ \vec{E}=E _{0}\hat{x} $ where $ E _{0} $ is a constant. The flux through the shaded area () due to this field is

Options:

A) $ 2E _{0}a^{2} $

B) $ \sqrt{2}E _{0}a^{2} $

C) $ E _{0}a^{2} $

D) $ \frac{E _{0}a^{2}}{\sqrt{2}} $

Show Answer

Answer:

Correct Answer: C

Solution:

[c] $ \int _{{}}^{{}}{\vec{E}.\overrightarrow{dA}=\phi } $

$ \Rightarrow \phi =E _{0}(a\times a\sqrt{2})\cos 45{}^\circ -E _{0}a^{2} $



NCERT Chapter Video Solution

Dual Pane