SATHEE: Electrostatics Question 715

Electrostatics Question 715

Question: Two very long line charges of uniform charge density $+ λ$ and $- λ$ are placed along same line with the separation between the nearest ends being 2a, . The electric field intensity at point O is

Options:

A) $\frac{λ}{2 π ε_{0} a}$

B) 0

C) $\frac{λ}{π ε_{0} a}$

D) $\frac{λ}{4 π ε_{0} a}$

Show Answer

Answer:

Correct Answer: A

Solution:

[a] The field at O due to small element

$d x$ is $d E = \frac{1}{4 π ε_{0}} \cdot \frac{λ d x}{x^{2}}$

Hence, due to one wire, $E_{1} = \int_{a}^{\infty} \frac{1}{4 π ε_{0}} \cdot \frac{λ d x}{x^{2}} E_{1} = \frac{1}{4 π ε_{0}} \cdot \frac{λ}{a}$ towards left.

Electric field at O due to other wire, $E_{2} = \frac{1}{4 π ε_{0}} \cdot \frac{λ}{a}$ towards left $∴$ Net field at O is $E = 2 \times \frac{1}{4 π ε_{0}} \cdot \frac{λ}{a} = \frac{λ}{2 π ε_{0} a}$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Electrostatics Question 715

Question: Two very long line charges of uniform charge density +λ and −λ are placed along same line with the separation between the nearest ends being 2a, . The electric field intensity at point O is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

Question: Two very long line charges of uniform charge density $+ λ$ and $- λ$ are placed along same line with the separation between the nearest ends being 2a, . The electric field intensity at point O is