SATHEE: Electrostatics Question 706

Electrostatics Question 706

Question: An electric dipole is placed at an angle of $30^{\circ}$ with an electric field of intensity $2 \times 10^{5} N C^{- 1}$ , it experiences a torque of 4 Nm. Calculate the charge on the dipole if the dipole length is 2 cm.

Options:

A) $8 m C$

B) $4 m C$

C) $8 μ C$

D) $2 m C$

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Torque, $\vec{τ} = \vec{p} \times \vec{E} = p E \sin θ$

$4 = p \times 2 \times 10^{5} \times \sin 30^{\circ}$

$or, p = \frac{4}{2 \times 10^{5} \times \sin 30^{\circ}} = 4 \times 10^{- 5} C m$ Dipole moment, $p = q \times l$

$q = \frac{p}{l} = \frac{4 \times 10^{- 5}}{0.02} = 2 \times 10^{- 3} C = 2 m C$

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Electrostatics Question 706

Question: An electric dipole is placed at an angle of 30∘ with an electric field of intensity 2×105NC−1 , it experiences a torque of 4 Nm. Calculate the charge on the dipole if the dipole length is 2 cm.

Options:

Answer:

Solution:

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Question: An electric dipole is placed at an angle of $30^{\circ}$ with an electric field of intensity $2 \times 10^{5} N C^{- 1}$ , it experiences a torque of 4 Nm. Calculate the charge on the dipole if the dipole length is 2 cm.