Electrostatics Question 703

Question: ABC is an equilateral triangle. Charges +q are placed at each corner as shown in fig. The electric intensity at center O will be

Options:

A) $ \frac{1}{4\pi {\in _{0}}}\frac{q}{r} $

B) $ \frac{1}{4\pi {\in _{0}}}\frac{q}{r^{2}} $

C) $ \frac{1}{4\pi {\in _{0}}}\frac{3q}{r^{2}} $

D) Zero

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Answer:

Correct Answer: D

Solution:

[d] Unit positive charge at 0 will be repelled equally by three charges at the three corners of triangle. By symmetry, relsultant

$ \vec{E} $ at O would be zero.



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