Electrostatics Question 690

Question: In fig., two equal positive point charges $ q _{1}=q _{2}=2.0\mu C $ interact with a third point charge $ Q=4.0\mu C $ . The magnitude, as well as direction, of the net force on Q is

Options:

A) 0.23 N in the +x-direction

B) 0.46 N in the +x-direction

C) 0.23 N in the +x-direction

D) 0.46 N in the +x-direction

Show Answer

Answer:

Correct Answer: B

Solution:

[b] $ F _{net}=2|F _{31}|cos\alpha $

$ =2\times \frac{1}{4\pi {\varepsilon _{0}}}\times \frac{2\times 4\times {{10}^{-12}}}{{{( 0.5 )}^{2}}}\times \frac{4}{5}=0.46N $



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