Electrostatics Question 660

Question: Two identical thin rings each of radius R meters are coaxially placed at a distance R meters apart. If Q1 coulomb and Q2 coulomb are respectively the charges uniformly spread on the two rings, the work done in moving a chargeq from the centre of one ring to that of other is

Options:

A) Zero

B) q(Q2Q1)(21)2.4πε0R

C) q2(Q1+Q2)4πε0R

D) q(Q1+Q2)(2+1)2.4πε0R

Show Answer

Answer:

Correct Answer: B

Solution:

[b] W=q(VO2VO1)

Where VO1=Q14πε0R+Q24πε0R2

And VO2=Q24πε0R+Q14πε0R2

VO2VO1=(Q2Q1)4πε0R[112] So, W=q.(Q2Q1)4πε0R(21)2



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