SATHEE: Electrostatics Question 656

Electrostatics Question 656

Question: A soap bubble (surface tension = $T$ ) is charged to a maximum surface density of charge = $σ$ . When it is just going to burst? Its radius R is given by

Options:

A) $R = \frac{σ^{2}}{8 ε_{0} T}$

B) $R = 8 ε_{0} \frac{T}{σ^{2}}$

C) $R = \frac{σ^{}}{\sqrt{8 ε_{0} T}}$

D) $R = \frac{{\sqrt{8 ε_{0} T}}^{}}{σ}$

Show Answer

Answer:

Correct Answer: B

Solution:

[b] The pressure due to surface tension $= \frac{4 T}{R}$ The pressure due to electrostatic forces $= \frac{σ^{2}}{2 ε_{0}}$ Just before the bubble bursts. $\frac{4 T}{R} = \frac{σ^{2}}{2 ε_{0}}$ or $R = \frac{8 T ε_{0}}{σ^{2}}$

Electrostatics Question 656

Question: A soap bubble (surface tension = $T$ ) is charged to a maximum surface density of charge = $σ$ . When it is just going to burst? Its radius R is given by

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Electrostatics Question 656

Question: A soap bubble (surface tension =T ) is charged to a maximum surface density of charge =σ . When it is just going to burst? Its radius R is given by

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

Question: A soap bubble (surface tension = $T$ ) is charged to a maximum surface density of charge = $σ$ . When it is just going to burst? Its radius R is given by