Electrostatics Question 655

Question: For section AB of a circuit ,$ C _{1}=1\mu F $ , $ C _{2}=2\mu F $ , $ E=10V $ , and the potential difference $ V _{A}-V _{B}=10V $ . Charge on capacitor $ C _{1} $ is

Options:

A) $ 0\mu C $

B) $ 20/3\mu C $

C) $ 40/3\mu C $

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

[c] $ V _{A}-\frac{q}{C _{1}}-E-\frac{q}{C _{2}}=V _{B} $ or $ V _{A}-V _{B}-E=q( \frac{1}{C _{1}}+\frac{1}{C _{2}} ) $ or $ q=-\frac{40}{3}\mu C $



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