Electrostatics Question 646

Question: The capacity of a parallel plate capacitor with no dielectric substance but with a separation of 0.4 cm is$ 2\mu F $ . The separation is reduced to half and it is filled with a dielectric substance of value 2.8. The final capacity of the capacitor is

Options:

A) $ 11.2\mu F $

B) $ 15.6\mu F $

C) $ 19.2\mu F $

D) $ 22.4\mu F $

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Answer:

Correct Answer: A

Solution:

[a] $ C=\frac{{\varepsilon _{0}}KA}{d}\Rightarrow \frac{C _{1}}{C _{2}}=\frac{K _{1}}{K _{2}}\times \frac{d _{2}}{d _{1}} $

$ \frac{2}{C _{2}}=\frac{1}{2.8}\times \frac{(0.4/2)}{(0.4)}\Rightarrow C _{2}=11.2\mu F $



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