SATHEE: Electrostatics Question 631

Electrostatics Question 631

Question: Three capacitors 2, 3 and 6 mF are joined in series with each other. What is the minimum effective capacitance [Orissa PMT 2004]

Options:

A) $\frac{1}{2} μ F$

B) 1 mF

C) 2 mF

D) 3 mF

Show Answer

Answer:

Correct Answer: B

Solution:

$\frac{1}{C_{e q}} = \frac{1}{C_{1}} + \frac{1}{C_{2}} + \frac{1}{C_{3}}$

$= \frac{1}{2} + \frac{1}{3} + \frac{1}{6}$

$= \frac{3 + 2 + 1}{6} = \frac{6}{6} = 1 μ F$

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Electrostatics Question 631

Question: Three capacitors 2, 3 and 6 mF are joined in series with each other. What is the minimum effective capacitance [Orissa PMT 2004]

Options:

Answer:

Solution:

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