Electrostatics Question 630

Question: Three plates of common surface area A are connected as shown. The effective capacitance will be [Orissa PMT 2004]

Options:

A) $ \frac{{\varepsilon _{0}}A}{d} $

B) $ \frac{3{\varepsilon _{0}}A}{d} $

C) $ \frac{3}{2}\frac{{\varepsilon _{0}}A}{d} $

D) $ \frac{2{\varepsilon _{0}}A}{d} $

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Answer:

Correct Answer: D

Solution:

The given circuit is equivalent to parallel combination of two identical capacitors, each having capacitance $ C=\frac{{\varepsilon _{0}}A}{d} $ .

Hence $ C _{eq}=2C=\frac{2{\varepsilon _{0}}A}{d} $



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