Electrostatics Question 612

Question: Three capacitors of $ 2\mu F,3\mu F $ and $ 6\mu F $ are joined in series and the combination is charged by means of a 24 volt battery. The potential difference between the plates of the $ 6\mu F $ capacitor is [MP PMT 2002]

Options:

A) 4 volt

B) 6 volt

C) 8 volt

D) 10 volt

Show Answer

Answer:

Correct Answer: A

Solution:

$ \frac{1}{C _{eq}}=\frac{1}{2}+\frac{1}{3}+\frac{1}{6}\Rightarrow C _{eq}=1\mu F $

Total charge Q = Ceq.V = 1 × 24 = 24 mC

So p.d. across 6 mF capacitor = $ \frac{24}{6}=4volt $



NCERT Chapter Video Solution

Dual Pane