Electrostatics Question 611

Question: Two capacitors $ {C _{\text{1}}} $ and $ {C _{\text{2}}}=\text{ 2}{C _{\text{1}}} $ are connected in a circuit with a switch between them . Initially the switch is open and $ {C _{\text{1}}} $ holds charge Q. The switch is closed. At steady state, the charge on each capacitor will be [Orissa JEE 2002]

Options:

A) $ Q,2Q $

B) $ Q/3,2Q/3 $

C) $ 3Q/2,3Q $

D) $ 2Q/3,4Q/3 $

Show Answer

Answer:

Correct Answer: B

Solution:

In steady state charge on C1 is $ Q _{1}=( \frac{C _{1}}{C _{1}+C _{2}} )\times Q=\frac{Q}{3} $ and charge on C2 is $ Q _{2}=( \frac{C _{2}}{C _{1}+C _{2}} ).Q=\frac{2}{3}Q $



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