SATHEE: Electrostatics Question 6

Electrostatics Question 6

Question: Which one statement is correct? A parallel plate air condenser is connected with a battery. Its charge, potential, electric field and energy are $Q_{o}, V_{o}, E_{o}$ and $U_{o}$ respectively. In order to fill the complete space between the plates a dielectric slab is inserted, the battery is still connected. Now the corresponding values $Q, V, E$ and $U$ are in relation with the initially stated as [IIT 1985]

Options:

A) $Q > Q_{o}$

B) $V > V_{o}$

C) $E > E_{o}$

D) $U > U_{o}$

Show Answer

Answer:

Correct Answer: A

Solution:

Capacitance will be increased when a dielectric is introduced in the capacitor but potential difference will remain the same because battery is still connected. So according to q = CV, charge will increase i.e. $Q > Q_{0}$ and $U = \frac{1}{2} Q V_{0}, U_{0} = \frac{1}{2} Q_{0} V_{0}$

therefore $Q > Q_{0}$ so $U > U_{0}$

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Electrostatics Question 6

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