Electrostatics Question 590

Question: The equivalent capacitance between A and B is [RPMT 1999]

Options:

A) 2μF

B) 3μF

C) 5μF

D) 0.5μF

Show Answer

Answer:

Correct Answer: D

Solution:

1C=12+11+12=1+2+12=42=2 therefore CAB=0.5μF



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