Electrostatics Question 590

Question: The equivalent capacitance between A and B is [RPMT 1999]

Options:

A) 2$ \mu F $

B) 3$ \mu F $

C) 5$ \mu F $

D) 0.5$ \mu F $

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Answer:

Correct Answer: D

Solution:

$ \frac{1}{C}=\frac{1}{2}+\frac{1}{1}+\frac{1}{2}=\frac{1+2+1}{2}=\frac{4}{2}=2 $ therefore $ C _{AB}=0.5\mu F $



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